Lesson 12
Arithmetic with Complex Numbers
- Let’s work with complex numbers.
Problem 1
Write each expression in the form \(a+bi\), where \(a\) and \(b\) are real numbers. You may plot the numbers in the complex plane as a guide.
- \(2 \boldcdot \sqrt{\text-4}\)
- \(3i \boldcdot 2i\)
- \(i^4\)
- \(4 - 3\sqrt{\text-1}\)
Problem 2
Which expression is equivalent to \((3+9i) - (5-3i)\)?
\(\text-2 - 12i\)
\(\text-2 + 12i\)
\(15 + 27i\)
\(15 - 27i\)
Problem 3
What are \(a\) and \(b\) when you write \(\sqrt{\text-16}\) in the form \(a+bi\), where \(a\) and \(b\) are real numbers?
\(a=0\), \(b=\text-4\)
\(a=0\), \(b=4\)
\(a=\text-4\), \(b=0\)
\(a=4\), \(b=0\)
Problem 4
Fill in the boxes to make a true statement:
\(\displaystyle (\boxed{\phantom{30}}-3i) - (15+\boxed{\phantom{30}}i) = 7 - 12i\)
Problem 5
Plot each number on the real number line, or explain why the number is not on the real number line.
- \(\sqrt{16}\)
- \(\text- \sqrt{16}\)
- \(\sqrt{\text-16}\)
- \(56^{1/2}\)
- \(\text- 56^{1/2}\)
-
\((\text-56)^{1/2}\)
Problem 6
Which expression is equivalent to \(\sqrt{\text-4}\)?
\(\text-2i\)
\(\text-4i\)
\(2i\)
\(4i\)