Unit 2 Family Materials
Polynomials and Rational Functions
Polynomials and Rational Functions
In this unit, your student will learn about a kind of function, polynomials. (In earlier grades, students learned about two special kinds of polynomial functions: linear and quadratic functions.) A polynomial is a sum of terms involving only one letter, called a variable, where the exponents of the variable are whole numbers. For example, \(3x^3  x^2 + 10\) and \(5x^6\) are polynomials. But \(6x^{\text2} + 2x^{\text1}\) is not, because the exponents are negative. And \(2xy  7x\) is not, because it involves more than one variable. Your student will connect different ways of representing polynomial functions, such as graphs and equations.
Multiplication and division of numbers will be extended to polynomials, so this is a good time to refresh skills with multiplying and dividing numbers by hand. When numbers are multiplied, we often use the distributive property, so that each piece of one number is multiplied by each piece of the other number. For example, 34 is 30 plus 4, or 3 tens plus 4 ones. The tens and ones of each number are multiplied by the tens and ones of the other, and then all the results are added. When polynomials are multiplied, we also use the distributive property. Here is an example of each:
\(\displaystyle \begin{array}{l} (30+4)(10+5) \\ = 30(10+5) + 4(10+5) \\ = 30 \boldcdot 10 + 30 \boldcdot 5 + 4 \boldcdot 10 + 4 \boldcdot 5 \\ = 300+150+40+20 \\ = 510 \end{array} \)
\(\displaystyle \begin{array}{l} (x7)(2x+3) \\ = x (2x+3) + (\text 7)(2x + 3) \\ = x \boldcdot 2x + x \boldcdot 3 + (\text 7) \boldcdot 2x + (\text 7) \boldcdot 3 \\ = 2x^2+3x14x21 \\ = 2x^2  11x  21 \end{array} \)
Multiplication, with numbers or polynomials, can be represented in lots of ways, and your student should find a way that makes sense and is useful. Ask your student to show you how to multiply polynomials.
Long division with polynomials looks a lot like long division with numbers. Here is an example of each:
\(\displaystyle \require{enclose} \begin{array}{r} \phantom{0}31 \\ 12 \enclose{longdiv}{372} \\ \underline{36\phantom{0}} \\ \phantom{0}12 \\ \phantom{0}\underline{12} \\ \phantom{00}0 \end{array} \)
\(\displaystyle \require{enclose} \begin{array}{r} \phantom{0}3x + 1 \\ x+2 \enclose{longdiv}{3x^2 + 7x + 2} \\ \underline{3x^2  6x \kern 1.8em} \\ x+2 \\ \underline{x  2} \\ 0 \end{array} \)
Division can also be represented in many ways, so if you or your student learned a different way of doing long division, that way can also be extended to polynomials.
Here are some tasks to try with your student:
 Multiply 47 by 25, using any method you like. Try using that same method to multiply \((4x + 7)(2x + 5)\). What was the same? What was different?
 Divide 372 by 12, using any method you like. Then represent the division another way, for example using pictures or words.
 Factor these expressions. Check your answers by multiplying the factors. When you were factoring and multiplying, how did you know what to do at each step?
 \(x^2 + 5x + 6\)
 \(x^2 + 2x  8\)
Solution:

One way to multiply 47 by 25 is to use a standard multiplication algorithm. We can do something similar with \((4x+7)(2x+5)\). Just as we multiplied 47 by 5 and then by 20 and then added the results together, we can multiply \(4x+7\) by 5 and then by \(2x\) and then add the results together. Here are the two versions:
\(\displaystyle \begin{array}{r} 47 \\ \underline{\times 25} \\ 235 \\ \underline{+ 940} \\ 1175 \end{array}\)
\(\begin{array}{r} 4x + 7 \\ \underline{\times \phantom{0}2x+5} \\ 20x+35 \\ \underline{+ \phantom{0}8x^2 + 14x + \phantom{0}0} \\ 8x^2+34x+35 \\ \end{array}\)

One way to divide 372 by 12 is the standard division algorithm (shown earlier). Another way to do it is by subtraction. To be more efficient, we can take away groups of 120 (ten 12's) until the result is less than 120, and then take away groups of 12. We can take away three groups of 120 and 1 group of 12 from 372, and then we have nothing left over. So there are 31 groups of 12.


\(x^2+5x+6=(x+3)(x+2)\)
 \(x^2+2x8=(x+4)(x2)\)
