Lesson 12
Completing the Square (Part 1)
- Let’s learn a new method for solving quadratic equations.
Problem 1
Add the number that would make the expression a perfect square. Next, write an equivalent expression in factored form.
- \(x^2 - 6x\)
- \(x^2 + 2x\)
- \(x^2 + 14x\)
- \(x^2 - 4x\)
- \(x^2 + 24x\)
Problem 2
Mai is solving the equation \(x^2 + 12x = 13\). She writes:
\(\displaystyle \begin{align} x^2 + 12x &= 13\\ (x + 6)^2 &= 49\\ x &= 1 \text { or } x = \text- 13\\ \end{align}\\\)
Jada looks at Mai’s work and is confused. She doesn’t see how Mai got her answer.
Complete Mai’s missing steps to help Jada see how Mai solved the equation.
Problem 3
Match each equation to an equivalent equation with a perfect square on one side.
Problem 4
Solve each equation by completing the square.
\(x^2-6x+5=12\)
\(x^2-2x=8\)
\(11=x^2+4x-1\)
\(x^2-18x+60=\text-21\)
Problem 5
Rewrite each expression in standard form.
- \((x+3)(x-3)\)
- \((7+x)(x-7)\)
- \((2x-5)(2x+5)\)
- \((x+\frac18)(x-\frac18)\)
Problem 6
To find the product \(203 \boldcdot 197\) without a calculator, Priya wrote \((200+3)(200-3)\). Very quickly, and without writing anything else, she arrived at 39,991. Explain how writing the two factors as a sum and a difference may have helped Priya.
Problem 7
A basketball is dropped from the roof of a building and its height in feet is modeled by the function \(h\).
Here is a graph representing \(h\).
Select all the true statements about this situation.
When \(t=0\) the height is 0 feet.
The basketball falls at a constant speed.
The expression that defines \(h\) is linear.
The expression that defines \(h\) is quadratic.
When \(t=0\) the ball is about 50 feet above the ground.
The basketball lands on the ground about 1.75 seconds after it is dropped.
Problem 8
A group of students are guessing the number of paper clips in a small box.
The guesses and the guessing errors are plotted on a coordinate plane.
What is the actual number of paper clips in the box?