Lesson 6

Side-Angle-Side Triangle Congruence

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Problem 1

Triangle \(DAC\) is isosceles with congruent sides \(AD\) and \(AC\). Which additional given information is sufficient for showing that triangle \(DBC\) is isosceles? Select all that apply.

Triangle ACD with point B near the center. Line segment AC is congruent to AD.
A:

Line \(AB\) is an angle bisector of \(DAC\).

B:

Angle \(BAD\) is congruent to angle \(ABC\).

C:

Angle \(BDC\) is congruent to angle \(BCD\).

D:

Angle \(ABD\) is congruent to angle \(ABC\).

E:

Triangle \(DAB\) is congruent to triangle \(CAB\).

Solution

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Problem 2

Tyler has written an incorrect proof to show that quadrilateral \(ABCD\) is a parallelogram. He knows segments \(AB\) and \(DC\) are congruent. He also knows angles \(ABC\) and \(ADC\) are congruent. Find the mistake in his proof.

Segment \(AC\) is congruent to itself, so triangle \(ABC\) is congruent to triangle \(ADC\) by Side-Angle-Side Triangle Congruence Theorem.  Since the triangles are congruent, so are the corresponding parts, and so angle \(DAC\) is congruent to \(ACB\).  In quadrilateral \(ABCD\), \(AB\) is congruent to \(CD\) and \(AD\) is parallel to \(CB\). Since \(AD\) is parallel to \(CB\), alternate interior angles \(DAC\) and \(BCA\) are congruent. Since alternate interior angles are congruent, \(AB\) must be parallel to \(CD\). Quadrilateral \(ABCD\) must be a parallelogram since both pairs of opposite sides are parallel.

Triangle ABC and ACD.

Solution

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Problem 3

Triangles \(ACD\) and \(BCD\) are isosceles. Angle \(BAC\) has a measure of 18 degrees and angle \(BDC\) has a measure of 48 degrees. Find the measure of angle \(ABD\).

\(\overline{AD} \cong \overline{AC}\) and \(\overline{BD} \cong \overline{BC}\)

Triangle A C D, isosceles, point B inside. Side A D and A C have one tick mark. Segments B D, B C, and BA are drawn. Triangle B C D is isosceles. Sides B D and B C have two tick marks.

Solution

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Problem 4

Here are some statements about 2 zigzags. Put them in order to prove figure \(ABC\) is congruent to figure \(DEF\).

Two figures, A B C and D E F.
  • 1: If necessary, reflect the image of figure \(ABC\) across \(DE\) to be sure the image of \(C\), which we will call \(C'\), is on the same side of \(DE\) as \(F\). 
  • 2: \(C'\) must be on ray \(EF\) since both \(C'\) and \(F\) are on the same side of \(DE\) and make the same angle with it at \(E\).
  • 3: Segments \(AB\) and \(DE\) are the same length so they are congruent. Therefore, there is a rigid motion that takes \(AB\) to \(DE\). Apply that rigid motion to figure \(ABC\).
  • 4: Since points \(C'\) and \(F\) are the same distance along the same ray from \(E\) they have to be in the same place.
  • 5: Therefore, figure \(ABC\) is congruent to figure \(DEF\).

Solution

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(From Unit 2, Lesson 5.)

Problem 5

Match each statement using only the information shown in the pairs of congruent triangles.

A:

The 2 angles and the included side of one triangle are congruent to 2 angles and the included side of another triangle.

B:

In the 2 triangles there are 3 pairs of congruent sides.

C:

The 2 sides and the included angle of one triangle are congruent to 2 sides and the included angle of another triangle.

1:
Two adjacent congruent angles. In each triangle, one side has one tick mark, the second side has 2 tick marks, and the 3rd side overlaps the other triangle.  
2:
Two triangles. In both triangles: an angle has an arc with a single tick mark, another angle has an arc with double tick marks, and the side in between the marked angles has a single tick mark.
3:
Two adjacent triangles.

Solution

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(From Unit 2, Lesson 4.)

Problem 6

Triangle \(ABC\) is congruent to triangle \(EDF\). So, Priya knows that there is a sequence of rigid motions that takes \(ABC\) to \(EDF\).  

Select all true statements after the transformations:

Triangle ABC is congruent to triangle EDF.
A:

Segment \(AB\) coincides with segment \(EF\).

B:

Segment \(BC\) coincides with segment \(DF\).

C:

Segment \(AC\) coincides with segment \(ED\).

D:

Angle \(A\) coincides with angle \(E\).

E:

Angle \(C\) coincides with angle \(F\).

Solution

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(From Unit 2, Lesson 3.)