Lesson 10
Calculating Slope
10.1: Number Talk: Integer Operations (5 minutes)
Warmup
Only three problems are given to allow time to discuss different values of \(a\) and \(b\) for each problem. It may not be possible to share every student’s responses, given limited time. Consider gathering only two or three different sets of values per problem. Each problem was chosen to elicit a different understanding of integer operations, so as students share theirs, ask how the information in the equation impacted their choices for \(a\) and \(b\).
This warmup is intended as an opportunity to review operations on positive and negative numbers.
Launch
Display the problems all at once. Give students 1 minute of quiet think time per problem and ask them to give a signal when they have at least one set of values for each question. Follow with a wholeclass discussion.
Supports accessibility for: Memory; Organization
Student Facing
Find values for \(a\) and \(b\) that make each side have the same value.
\(\frac{a}{b}=\text2\)
\(\frac{a}{b}=2\)
\(ab=\text2\)
Student Response
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Anticipated Misconceptions
Students may have forgotten that the quotient of two negative numbers is positive.
Activity Synthesis
Ask students to share their values for \(a\) and \(b\) for each problem. Include at least one set of values for each problem where \(a\) or \(b\) (or both) are negative. Record and display their values for \(a\) and \(b\) for all to see. Ask students how they decided on their values based on the information given in the equation. To involve more students in the conversation, consider asking:
 “Did anyone choose the same values?”
 “Who can restate ___’s reasoning in a different way?”
 “Did anyone choose different values?”
 “Does anyone want to add on to _____’s reasoning?”
 “Do you agree or disagree? Why?”
Design Principle(s): Optimize output (for explanation)
10.2: Toward a More General Slope Formula (15 minutes)
Activity
The purpose of this activity is to compute the slopes of different lines to get familiar with the formula “subtract \(y\)coordinates, subtract \(x\)coordinates, then divide.” Students first compute slopes for some lines with positive slopes, and then special attention is drawn to the fact that a line has a negative slope. Students attend to what makes the same computations have a negative result instead of a positive result.
Launch
Have partners figure out the slope of the line that passes through each pair of points.

\((12,4)\) and \((7,1)\) (answer: \(\frac35\))

\((4,\text{}11)\) and \((7,\text{}8)\) (answer: 1)

\((1,2)\) and (\(600,3)\) (answer: \(\frac{1}{599}\))

\((37,40)\) and \((30,33)\) (answer: 1)
Ask students to share their results and how they did it. Students may say they just found the difference between the numbers; making this more precise is part of the goal of the discussion for this activity. Ask students to complete the questions in the task and share their responses with a partner before class discussion. Provide access to graph paper and rulers.
Supports accessibility for: Memory; Language
Student Facing
 Plot the points \((1,11)\) and \((8, 2)\), and use a ruler to draw the line that passes through them.
 Without calculating, do you expect the slope of the line through \((1,11)\) and \((8, 2)\) to be positive or negative? How can you tell?
 Calculate the slope of this line.
Student Response
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Student Facing
Are you ready for more?
Find the value of \(k\) so that the line passing through each pair of points has the given slope.

\((k,2)\) and \((11,14)\), slope = 2

\((1,k)\) and \((4,1)\), slope = 2

\((3,5)\) and \((k,9)\), slope = \(\frac12\)

\((\text1,4)\) and \((\text3,k)\), slope = \(\frac{\text{}1}{2}\)

\((\frac {\text{}15}{2},\frac{3}{16})\) and \((\frac {\text{}13}{22},k)\), slope = 0
Student Response
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Anticipated Misconceptions
Students may struggle with operations on negative numbers and keeping everything straight if they try to take a purely algorithmic approach. Encourage them to plot both points and reason about the length of the vertical and horizontal portions of the slope triangle and the sign of the slope of the line, one step at a time. Sketching a graph of the line is also useful for verifying the sign of the line’s slope.
It is common for students to calculate a slope and leave it in a form such as \(\frac {\text{}3}{\text{}5}\). Remind students that this fraction is representing a division operation, and the quotient would be a positive value.
Activity Synthesis
When using two points to calculate the slope of a line, care needs to be taken to subtract the \(x\) and \(y\) values in the same order. Using the first pair as an example, the slope could be calculated either of these ways: \(\displaystyle \frac{41}{127}=\frac35\) \(\displaystyle \frac{14}{712}=\frac {\text{}3}{\text{}5}=\frac35\) But if one of the orders were reversed, this would yield a negative value for the slope when we know the slope should have a positive value.
It is worth demonstrating, or having a student demonstrate an algorithmic approach to finding the negative slope in the last part of the task. Draw attention to the fact that keeping the coordinates “in the same order” results in the numerator and denominator having opposite signs (one positive and one negative), so that their quotient must be negative. It might look like: \(\displaystyle \frac{112}{18}=\frac{9}{\text{}7}=\text{}\frac{9}{7}\)
Ask students how sketching a graph of the line will tell them whether the slope is positive or negative. They should recognize that when it goes up, from left to right, the slope is positive, and when it goes down, then the slope is negative. Using a sketch of the graph can also be helpful to judge whether the magnitude of the (positive or negative) slope is reasonable.
Design Principle(s): Optimize output (for comparison); Maximize metaawareness
10.3: Making Designs (20 minutes)
Activity
The goal of this activity is for students to recognize information that determines the location of a line in the coordinate plane, and to practice distinguishing between positive and negative slopes. In this activity, one partner has a design that they verbally describe to their partner, who then tries to draw it. The purpose of this activity is to provide an environment where students have to describe or interpret the slope and locations of several lines. (Students are not expected to communicate by saying the equations of the lines, though there is nothing stopping them from doing so.) Students take turns describing and interpreting by doing this two times with two different designs.
Monitor for students who use language of slope and vertical or horizontal intercepts to communicate the location of each line. Invite these students to share during the discussion. There are many other ways students might communicate the location of each line, but the recent emphasis on studying slope and intercepts should make these choices natural.
The two designs in the blackline masters look like this:
You will need the Info Gap: Making Designs blackline master for this activity.
Thanks to Henri Picciotto for permission to use these designs.
Launch
Tell students they will describe some lines to a partner to try and get them to recreate a design. The protocol is described in the student task statement. Consider asking a student to serve as your partner to demonstrate the protocol to the class before distributing the designs and blank graphs.
Arrange students in groups of 2. Provide access to straightedges.
From the blackline master that you have copied and cut up ahead of time, give one partner the design, and the other partner a blank graph. Arrange the room to ensure that the partner drawing the design cannot peek at the design anywhere in the room. Once the first design has been successfully created, provide the second design and a blank graph to the other student in each partnership.
Supports accessibility for: Language; Memory
Design Principle(s): Cultivate conversation
Student Facing
Your teacher will give you either a design or a blank graph. Do not show your card to your partner.
If your teacher gives you the design:
 Look at the design silently and think about how you could communicate what your partner should draw. Think about ways that you can describe what a line looks like, such as its slope or points that it goes through.
 Describe each line, one at a time, and give your partner time to draw them.
 Once your partner thinks they have drawn all the lines you described, only then should you show them the design.
If your teacher gives you the blank graph:
 Listen carefully as your partner describes each line, and draw each line based on their description.
 You are not allowed to ask for more information about a line than what your partner tells you.
 Do not show your drawing to your partner until you have finished drawing all the lines they describe.
When finished, place the drawing next to the card with the design so that you and your partner can both see them. How is the drawing the same as the design? How is it different? Discuss any miscommunication that might have caused the drawing to look different from the design.
Pause here so your teacher can review your work. When your teacher gives you a new set of cards, switch roles for the second problem.
Student Response
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Activity Synthesis
After students have completed their work, ask students to discuss the process of communicating how to draw a line. Some guiding questions:
 "What details were important to pay attention to?"
 "How did you use coordinates to help communicate where the line is?"
 "How did you use slope to communicate how to draw the line?"
 "Were there any cases where your partner did not give enough information to know where to draw the line? What more information did you need?"
Students might notice that the lines with the same slope can be described in terms of translations (for example, line \(b\) is a vertical translation of line \(a\) down two units). This is an appropriate use of rigid motion language which recalls work done earlier in this unit. Students might also describe \(b\) as parallel to \(a\) and containing the point \((0,3)\). Finally, some students might use equations to communicate the location of the lines. All of these methods are appropriate. Keep the discussion focused on describing each line using slope and coordinates for each individual line on its own.
Lesson Synthesis
Lesson Synthesis
In this lesson, students explored the interplay between the coordinates of points on a line and the slope of that line, where the slope could be positive or negative.
Ask students, “What information do you need to know exactly where a line is?” Valid responses might be the coordinates of two points on the line or the coordinates of one point and the line’s slope. Demonstrate why knowing one point is not enough information (the line goes through it, but could have any slope), and why only knowing the slope is not enough information (you know at what slope to draw the line, but it could be located anywhere—it could be any of a set of parallel lines). It can be helpful to use a yardstick to represent “the line” in this situation as you move it around a coordinate plane on the board.
Ask students, “If you know the coordinates of two points on a line, how can you tell if it has a positive or negative slope?” Responses might include sketching a graph of the line to see if it’s “uphill” or “downhill,” or an algorithm involving subtraction and division, attending to keeping coordinates in “the same order” and performing operations correctly.
10.4: Cooldown  Different Slopes (5 minutes)
CoolDown
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Student Lesson Summary
Student Facing
We learned earlier that one way to find the slope of a line is by drawing a slope triangle. For example, using the slope triangle shown here, the slope of the line is \(\text{}\frac24\), or \(\text{}\frac12\) (we know the slope is negative because the line is decreasing from left to right).
But slope triangles are only one way to calculate the slope of a line. Let’s compute the slope of this line a different way using just the points \(A=(1,5)\) and \(B=(5,3)\). Since we know the slope is the vertical change divided by the horizontal change, we can calculate the change in the \(y\)values and then the change in the \(x\)values. Between points \(A\) and \(B\), the \(y\)value change is \(35=\text{}2\) and the \(x\)value change is \(51=4\). This means the slope is \(\text{}\frac24\), or \(\text{}\frac12\), which is the same as what we found using the slope triangle.
Notice that in each of the calculations, We subtracted the value from point \(A\) from the value from point \(B\). If we had done it the other way around, then the \(y\)value change would have been \(53=2\) and the \(x\)value change would have been \(15=\text4\), which still gives us a slope of \(\text \frac12\). But what if we were to mix up the orders? If that had happened, we would think the slope of the line is positive \(\frac12\) since we would either have calculated \(\frac{\text2}{\text4}\) or \(\frac{2}{4}\). Since we already have a graph of the line and can see it has a negative slope, this is clearly incorrect. It we don’t have a graph to check our calculation, we could think about how the point on the left, \((1,5)\), is higher than the point on the right, \((5,3)\), meaning the slope of the line must be negative.