Lesson 4
Proportional Relationships and Equations
4.1: Number Talk: Division (5 minutes)
Warmup
This number talk encourages students to think about the numbers in division problems and how they can use the result of one division problem to find the answer to a similar problem with a different, but related, divisor. Four problems are given, however, given limited time it may not be possible to share every possible strategy. Consider gathering only two or three different strategies per problem. Each problem is chosen to elicit a slightly different reasoning, so, as students explain their strategies, ask how the factors impacted their product.
In the final question, ask students to choose a value for \(x\) for which they could easily find the quotient. If students do not use what they know based on the answer to the previous question, ask them if they could use what they know about that equation to reason about the last expression.
Launch
Display one problem at a time. Tell students to give a signal when they have an answer and a strategy. After each problem, give students 1 minute of quiet think time followed by a wholeclass discussion. Pause after discussing the third question and tell students they will be using patterns they noticed in the previous problems to choose their own divisor for the last problem. Keep all problems displayed throughout the talk.
Supports accessibility for: Memory; Organization
Student Facing
Find each quotient mentally.
\(645\div100\)
\(645\div50\)
\(48.6\div30\)
\(48.6\div x\)
Student Response
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Activity Synthesis
Ask students to share their strategies for each problem. Record and display their explanations for all to see. To involve more students in the conversation, consider asking:
 “Who can restate ___’s reasoning in a different way?”
 “Did anyone solve the problem the same way but would explain it differently?”
 “Did anyone solve the problem in a different way?”
 “Does anyone want to add on to _____’s strategy?”
 “Do you agree or disagree? Why?”
For the fourth question, ask students to share their divisor choice and reasoning behind the choice. Record these divisors for all to see and ask the rest of the class to find the quotient based on the divisor choice. Ask students to refer back to patterns and regularity they noticed in the first three problems that influenced their decisions.
Design Principle(s): Optimize output (for explanation)
4.2: Feeding a Crowd, Revisited (10 minutes)
Activity
This activity revisits a context seen previously. Students solved problems like this as early as grade 3 without formulating them in terms of ratios or rates (“If 1 cup of rice serves 3 people, how many people can you serve with 12 cups of rice?”). In this activity, they ultimately find an equation for the proportional relationship.
As students find missing values in the table, they should see that they can always multiply the number of food items by the constant of proportionality. When students see this pattern (MP7) and represent the number of people served by \(x\) cups of rice (or \(s\) spring rolls) as \(3x\) (or \(\frac{1}{2}s\)), they are expressing regularity in repeated reasoning (MP8).
Only one row in each table is complete. Based on their experience in the previous lesson, students are more likely to multiply the entries in the lefthand column by 3 (or \(\frac{1}{2}\)) than to use scale factors, at least for the first and third rows. If they do, they are more likely to see how to complete the last row in each table.
Some students might use unit rates: If 1 cup of rice can serve 3 people, then \(x\) cups of rice can serve \(3x\) people. So, students have different ways to generate \(3x\) as the expression that represents the number of people served by \(x\) cups of rice: completing the table for numerical values and continuing the pattern to the last row; or finding the unit rate and using it in the case of \(x\) cups.
Monitor students for different approaches as they are working.
Launch
Tell students that this activity revisits a context they worked on in an earlier lesson.
Student Facing

A recipe says that 2 cups of dry rice will serve 6 people. Complete the table as you answer the questions. Be prepared to explain your reasoning.

How many people will 1 cup of rice serve?

How many people will 3 cups of rice serve? 12 cups? 43 cups?

How many people will \(x\) cups of rice serve?
cups of dry rice number of people 1 2 6 3 12 43 \(x\) 

A recipe says that 6 spring rolls will serve 3 people. Complete the table as you answer the questions. Be prepared to explain your reasoning.
 How many people will 1 spring roll serve?
 How many people will 10 spring rolls serve? 16 spring rolls? 25 spring rolls?
 How many people will \(n\) spring rolls serve?
number of spring rolls number of people 1 6 3 10 16 25 \(n\)  How was completing this table different from the previous table? How was it the same?
Student Response
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Anticipated Misconceptions
If students have trouble encapsulating the relationship with an expression, encourage them to draw diagrams or to verbalize the relationship in words.
Activity Synthesis
Select students who have used the following approaches in the given order:
 Recognize that to move from the first column to the second, you multiply by 3.
 Say that 3 is the constant of proportionality.
 Recognize that the equation \(2 \boldcdot {?} = 6\) can be used to find the constant of proportionality algebraically.
 Say that the 3 can be interpreted as the number of people per 1 cup of rice.
If no student sees that these insights are connected to prior work, explicitly connect them with the lessons of the previous two days. At the end of the discussion, suggest to students that we let \(y\) represent the number of people who can be served by \(x\) cups of rice. Ask students to write an equation that gives the relationship of \(x\) and \(y\). (This builds on work from grade 6, but it may be rusty.) Be sure to write the equation \(y = 3x\) where all students can see it and help students interpret its meaning in the context: “To find \(y\), the number of people served, we can multiply the number of cups of rice, \(x\), by 3.”
Supports accessibility for: Visualspatial processing; Conceptual processing
Design Principle(s): Cultivate conversation; Maximize metaawareness
4.3: Denver to Chicago (10 minutes)
Activity
This activity revisits a context seen previously. This time, students represent the proportional relationship between distance and time with an equation. Students once again make use of structure (MP7) and use repeated reasoning (MP8), but there is also a focus on moving back and forth between the abstract representation and the context (MP2).
As part of this activity, students calculate distance and speed. Students should know from grade 6 that speed is the quotient of distance traveled by amount of time elapsed, so they can divide 915 by 1.5 to get the speed. Students that do not begin the problem in that way can be directed back to the similar task in previous lessons to make connections and correct themselves. Once students have the speed, which is constant throughout this problem, they identify this as the constant of proportionality and use it to find the missing values.
Monitor for students who solve the problem in different ways.
Launch
Tell students that this activity revisits a context from an earlier lesson.
Supports accessibility for: Memory; Conceptual processing
Design Principle(s): Maximize metaawareness, Maximize output
Student Facing
A plane flew at a constant speed between Denver and Chicago. It took the plane 1.5 hours to fly 915 miles.
 Complete the table.
time (hours) distance (miles) speed (miles per hour) 1 1.5 915 2 2.5 \(t\)  How far does the plane fly in one hour?
 How far would the plane fly in \(t\) hours at this speed?
 If \(d\) represents the distance that the plane flies at this speed for \(t\) hours, write an equation that relates \(t\) and \(d\).
 How far would the plane fly in 3 hours at this speed? in 3.5 hours? Explain or show your reasoning.
Student Response
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Student Facing
Are you ready for more?
A rocky planet orbits Proxima Centauri, a star that is about 1.3 parsecs from Earth. This planet is the closest planet outside of our solar system.
 How long does it take light from Proxima Centauri to reach Earth? (A parsec is about 3.26 light years. A light year is the distance light travels in one year.)
 There are two twins. One twin leaves on a spaceship to explore the planet near Proxima Centauri traveling at 90% of the speed of light, while the other twin stays home on Earth. How much does the twin on Earth age while the other twin travels to Proxima Centauri? (Do you think the answer would be the same for the other twin? Consider researching “The Twin Paradox” to learn more.)
Student Response
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Anticipated Misconceptions
Students who are having trouble understanding the task can draw a segment between Denver and Chicago and label it with the distance and the time. From there, they can draw a double number line diagram.
Activity Synthesis
Select students to discuss and share their solutions. Ask them to identify difficulties which might include: getting started, noticing the pattern, dividing with decimals, completing the values in the table, creating the equation. This problem increases the level of difficulty by having so much missing information, and by using decimals in the table. It is important to identify if there are parts that are confusing for students to move them forward.
As part of the discussion, write the equation for all to see, and ask students to describe in words how to interpret its meaning in the context of the situation. (To find \(d\), the distance traveled by the plane in miles, multiply the hours of travel, \(t\), by the plane’s speed in miles per hour, 610.)
4.4: Revisiting Bread Dough (10 minutes)
Optional activity
This activity gives students more practice writing an equation that represents the proportional relationship examined in a previous lesson: the amount of flour and honey in a recipe. Students can then use their equation to answer additional questions about the situation.
Launch
Tell students that this activity revisits a context from an earlier lesson. Give students quiet work time followed by partner discussion.
Design Principle(s): Support sensemaking
Student Facing
A bakery uses 8 tablespoons of honey for every 10 cups of flour to make bread dough. Some days they bake bigger batches and some days they bake smaller batches, but they always use the same ratio of honey to flour.
 Complete the table.
 If \(f\) is the cups of flour needed for \(h\) tablespoons of honey, write an equation that relates \(f\) and \(h\).

How much flour is needed for 15 tablespoons of honey? 17 tablespoons? Explain or show your reasoning.
honey (tbsp)  flour (c) 

1  
8  10 
16  
20  
\(h\) 
Student Response
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Activity Synthesis
Ask students to compare answers with their partner and discuss their reasoning until they reach an agreement.
Then, invite students to share how they used their equation from question 2 to answer question 3 with the whole class.
Lesson Synthesis
Lesson Synthesis
Briefly revisit the three activities, demonstrating the use of new and old terms. For example:
 We examined a proportional relationship between cups of rice and people served. What was the constant of proportionality in this task? What did the constant of proportionality represent? What equation did we write for this situation?
 We examined a proportional relationship where we knew that a plane was flying at a constant speed. What was the constant of proportionality for this relationship? What does the constant of proportionality represent in terms of the context? What equation did we determine would represent this situation?
As a way to help students synthesize their learning, consider asking them to work with a partner and create a mind map of the features they have noticed these proportional relationships have in common. You might collect these to check for understanding. A class version can be created to be referenced, revised, or augmented during the unit.
4.5: Cooldown  It’s Snowing in Syracuse (5 minutes)
CoolDown
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Student Lesson Summary
Student Facing
The table shows the amount of red paint and blue paint needed to make a certain shade of purple paint, called Venusian Sunset.
Note that “parts” can be any unit for volume. If we mix 3 cups of red with 12 cups of blue, you will get the same shade as if we mix 3 teaspoons of red with 12 teaspoons of blue.
red paint (parts) 
blue paint (parts) 

3  12 
1  4 
7  28 
\(\frac14\)  1 
\(r\)  \(4 r\) 
The last row in the table says that if we know the amount of red paint needed, \(r\), we can always multiply it by 4 to find the amount of blue paint needed, \(b\), to mix with it to make Venusian Sunset. We can say this more succinctly with the equation \(b=4 r\). So the amount of blue paint is proportional to the amount of red paint and the constant of proportionality is 4.
We can also look at this relationship the other way around.
If we know the amount of blue paint needed, \(b\), we can always multiply it by \(\frac14\) to find the amount of red paint needed, \(r\), to mix with it to make Venusian Sunset. So \(r=\frac14 b\). The amount of red paint is proportional to the amount of blue paint and the constant of proportionality \(\frac14\).
blue paint (parts) 
red paint (parts) 

12  3 
4  1 
28  7 
1  \(\frac14\) 
\(b\)  \(\frac14 b\) 
In general, when \(y\) is proportional to \(x\), we can always multiply \(x\) by the same number \(k\)—the constant of proportionality—to get \(y\). We can write this much more succinctly with the equation \(y=k x\).