Lesson 12
Applications of Arithmetic with Powers of 10
Problem 1
Which is larger: the number of meters across the Milky Way, or the number of cells in all humans? Explain or show your reasoning.
Some useful information:
- The Milky Way is about 100,000 light years across.
- There are about 37 trillion cells in a human body.
- One light year is about \(10^{16}\) meters.
- The world population is about 7 billion.
Solution
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Problem 2
Write each number in scientific notation.
- 14,700
- 0.00083
- 760,000,000
- 0.038
- 0.38
- 3.8
- 3,800,000,000,000
- 0.0000000009
Solution
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Problem 3
Perform the following calculations. Express your answers in scientific notation.
-
\((2 \times 10^5) + (6 \times 10^5)\)
-
\((4.1 \times 10^7) \boldcdot 2\)
-
\((1.5 \times 10^{11}) \boldcdot 3\)
-
\((3 \times 10^3)^2\)
- \((9 \times 10^6) \boldcdot (3 \times 10^6)\)
Solution
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Problem 4
Jada is making a scale model of the solar system. The distance from Earth to the Moon is about \(2.389 \times 10^5\) miles. The distance from Earth to the Sun is about \(9.296 \times 10^7\) miles. She decides to put Earth on one corner of her dresser and the Moon on another corner, about a foot away. Where should she put the sun?
- On a windowsill in the same room?
- In her kitchen, which is down the hallway?
- A city block away?
Explain your reasoning.
Solution
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Problem 5
Diego was solving an equation, but when he checked his answer, he saw his solution was incorrect. He knows he made a mistake, but he can’t find it. Where is Diego’s mistake and what is the solution to the equation?
\(\displaystyle \begin{align} \text-4(7-2x)=3(x+4)\\ \text-28-8x=3x+12\\ \text-28=11x+12\\ \text-40=11x\\ \text{-}\frac {40}{11}=x\ \end{align}\)
Solution
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(From Unit 4, Lesson 13.)Problem 6
Here is the graph for one equation in a system of equations.
- Write a second equation for the system so it has infinitely many solutions.
- Write a second equation whose graph goes through \((0,2)\) so that the system has no solutions.
- Write a second equation whose graph goes through \((2,2)\) so that the system has one solution at \((4,3)\).
Solution
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(From Unit 5, Lesson 13.)